DelMonte, Guidubaldo, Le mechaniche

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    <archimedes>
      <text id="id.0.0.0.0.3">
        <body id="id.2.0.0.0.0">
          <chap id="N13354">
            <pb xlink:href="037/01/120.jpg"/>
            <p id="id.2.1.649.0.0" type="main">
              <s id="id.2.1.649.1.0">
                <emph type="italics"/>
              Sia il peſo A come cento, & la poſſanza che ha da mouere ſia come diece; & ſia
                <lb/>
              la data leua BC. </s>
              <s id="id.2.1.649.2.0">Egli è biſogno che la poſſanza, che è diece moua il peſo A, che
                <lb/>
              è cento, con la leua BC. </s>
              <s id="id.2.1.649.3.0">Diuidaſi BC in D con ſi fatta maniera che CD hab
                <lb/>
              bia la proportione medeſima à DB, che ha cento à diece, cioè diece ad vno; per­
                <emph.end type="italics"/>
                <lb/>
                <figure id="id.037.01.120.1.jpg" xlink:href="037/01/120/1.jpg" number="116"/>
                <lb/>
                <arrow.to.target n="note190"/>
                <emph type="italics"/>
              cioche ſe D ſi faceſſe ſoſtegno, egli è manifeſto, che la poſſanza in C come diece
                <lb/>
              peſerà egualmente co'l peſo A appiccato in B, cioè che ſoſterrà il peſo A. </s>
              <s id="id.2.1.649.4.0">Pren
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="note191"/>
                <emph type="italics"/>
              daſi tra BD qual ſi voglia punto, come E, & facciaſi E il ſoſtegno. </s>
              <s id="id.2.1.649.5.0">Hor per­
                <lb/>
              cioche maggiore è la proportione di CE ad EB, che di CD à DB; CE haurà
                <lb/>
              proportione maggiore ad EB, che il peſo A alla poſſanza di diece poſta in C;
                <lb/>
              dunque la poſſanza di diece poſta in C mouerà il peſo A, che è cento, appiccato
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="note192"/>
                <emph type="italics"/>
              in B con la leua BC, che ha il ſuo ſoſtegno E.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.651.0.0" type="margin">
              <s id="id.2.1.651.1.0">
                <margin.target id="note190"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              1.
                <emph type="italics"/>
              di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.652.0.0" type="margin">
              <s id="id.2.1.652.1.0">
                <margin.target id="note191"/>
                <emph type="italics"/>
              Per lo lemma di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.653.0.0" type="margin">
              <s id="id.2.1.653.1.0">
                <margin.target id="note192"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              11.
                <emph type="italics"/>
              di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.654.0.0" type="main">
              <s id="id.2.1.654.1.0">
                <emph type="italics"/>
              Ma ſe la leua foſſe BC, & il ſoſtegno B. </s>
              <s id="N14ADE">diuidaſi CB in D per ſi fatta maniera,
                <lb/>
              che CB habbia la proportione iſteſſa à BD, che ha cento à diece: & ſe il peſo
                <lb/>
              A ſarà appic
                <lb/>
              cato in D, &
                <lb/>
              la poſſanza in
                <lb/>
              C, la poſſan­
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="note193"/>
                <emph type="italics"/>
              za in C come
                <lb/>
              diece ſoſterrà
                <lb/>
              anco il peſo
                <lb/>
              A appiccato
                <emph.end type="italics"/>
                <lb/>
                <figure id="id.037.01.120.2.jpg" xlink:href="037/01/120/2.jpg" number="117"/>
                <lb/>
                <emph type="italics"/>
              in D. </s>
              <s id="id.2.1.654.2.0">Prendaſi qual ſi uoglia punto tra DB, come E, & pongaſi il peſo A in
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="note194"/>
                <emph type="italics"/>
              E; & per eſſere proportione maggiore da CB à BE, che da BC à BD; CB
                <lb/>
              haurà proportione maggiore à BE, che il peſo A di cento alla poſſanza di diece.
                <lb/>
              </s>
              <s id="id.2.1.654.3.0">Dunque la poſſanza di diece poſta in C mouerà il peſo A di cento appiccato in E
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="note195"/>
                <emph type="italics"/>
              con la leua BC, che ha il ſoſtegno ſuo B. </s>
              <s id="N14B20">che biſognaua menar ad effetto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.656.0.0" type="margin">
              <s id="id.2.1.656.1.0">
                <margin.target id="note193"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              2.
                <emph type="italics"/>
              di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.657.0.0" type="margin">
              <s id="id.2.1.657.1.0">
                <margin.target id="note194"/>
                <emph type="italics"/>
              Per la ottaua del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.658.0.0" type="margin">
              <s id="id.2.1.658.1.0">
                <margin.target id="note195"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              11.
                <emph type="italics"/>
              di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.659.0.0" type="main">
              <s id="id.2.1.659.1.0">
                <emph type="italics"/>
              Ma ciò non ſi puote mandar' ad eſecutione con la leua BC, che habbia il ſoſtegno ſuo
                <lb/>
              in B, & il peſo A di cento ſia appiccato in C. </s>
              <s id="id.2.1.659.2.0">Percioche pongaſi la poſſanza
                <lb/>
              ſoſtenente il peſo A comunque ſi ſia tra BC, come in D; ſempre la poſſanza
                <lb/>
              ſarà maggiore del peſo A. </s>
              <s id="id.2.1.659.3.0">Per laqual coſa egli è meſtieri che ſempre la data poſ­
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>
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