Valerio, Luca
,
De centro gravitatis solidorum
,
1604
Text
Text Image
Image
XML
Thumbnail overview
Document information
None
Concordance
Figures
Thumbnails
List of thumbnails
<
1 - 10
11 - 20
21 - 30
31 - 40
41 - 50
51 - 60
61 - 70
71 - 80
81 - 90
91 - 100
101 - 110
111 - 120
121 - 130
131 - 140
141 - 150
151 - 160
161 - 170
171 - 180
181 - 190
191 - 200
201 - 210
211 - 220
221 - 230
231 - 240
241 - 250
251 - 260
261 - 270
271 - 280
281 - 283
>
11
12
13
14
15
16
17
18
19
20
<
1 - 10
11 - 20
21 - 30
31 - 40
41 - 50
51 - 60
61 - 70
71 - 80
81 - 90
91 - 100
101 - 110
111 - 120
121 - 130
131 - 140
141 - 150
151 - 160
161 - 170
171 - 180
181 - 190
191 - 200
201 - 210
211 - 220
221 - 230
231 - 240
241 - 250
251 - 260
261 - 270
271 - 280
281 - 283
>
page
|<
<
of 283
>
>|
<
archimedes
>
<
text
>
<
body
>
<
chap
>
<
p
type
="
main
">
<
s
>
<
pb
xlink:href
="
043/01/017.jpg
"
pagenum
="
9
"/>
ad triangulum FBG, hoc eſt vt AF ad FG, ita eſt
<
lb
/>
triangulum AFC ad triangulum FCG; triangulum er
<
lb
/>
go FBG triangulo FCG æquale erit, & baſis BG ba
<
lb
/>
ſi GC æqualis. </
s
>
<
s
>Quoniam igitur & AE eſt æqualis
<
lb
/>
EC, ſimiliter vt ante, oſtenderemus, triangulum BCF,
<
lb
/>
triangulo ACF, eademque ratione triangulum ABF,
<
lb
/>
triangulo BCF æquale eſſe: igitur vnumquodque trian
<
lb
/>
gulorum ABF, ACF, BCF, tertia pars eſt trianguli
<
lb
/>
ABC: ſed vt triangulum ABC, ad triangulum BCF,
<
lb
/>
ita eſt AG, ad GF; tripla igitur eſt AG ipſius GF,
<
lb
/>
ac proinde AF, ipſius FG dupla. </
s
>
<
s
>Eadem ratione
<
lb
/>
BE, ipſius FE, & CF, ipſius FD, dupla concludetur. </
s
>
</
p
>
<
p
type
="
main
">
<
s
>Sed ſint ſi fieri poteſt, trianguli ABC duo centra qua
<
lb
/>
lia diximus D, E: & ab ipſis ad ſingulos angulos du
<
lb
/>
cantur binæ rectæ lineæ:
<
lb
/>
& eadat D in aliquo trian
<
lb
/>
gulo BEC. </
s
>
<
s
>Quoniam
<
lb
/>
igitur D eſt centrum trian
<
lb
/>
guli ABC erit triangu
<
lb
/>
lum BDC tertia pars
<
lb
/>
trianguli ABC. </
s
>
<
s
>Eadem
<
lb
/>
ratione triangulum BEC
<
lb
/>
tertia pars erit trianguli
<
lb
/>
ABC; triangulum ergo
<
lb
/>
DBC æquale erit trian
<
lb
/>
gulo BEC pars toti, quod
<
lb
/>
fieri non poteſt, atqui
<
expan
abbr
="
idẽ
">idem</
expan
>
<
lb
/>
<
figure
id
="
id.043.01.017.1.jpg
"
xlink:href
="
043/01/017/1.jpg
"
number
="
8
"/>
<
lb
/>
abſurdum ſequitur, ſi punctum D cadat in aliquo latere
<
lb
/>
triangulorum, quorum vertex E; Manifeſtum eſt igitur
<
lb
/>
propoſitum. </
s
>
</
p
>
</
chap
>
</
body
>
</
text
>
</
archimedes
>