Casati, Paolo, Fabrica, et uso del compasso di proportione, dove insegna à gli artefici il modo di fare in esso le necessarie divisioni, e con varij problemi ...

Table of figures

< >
[Figure 51]
Page: 185
[Figure 52]
Page: 185
[Figure 53]
Page: 188
[Figure 54]
Page: 190
[Figure 55]
Page: 192
[Figure 56]
Page: 198
[Figure 57]
Page: 199
[Figure 58]
Page: 200
[Figure 59]
Page: 203
[Figure 60]
Page: 207
[Figure 61]
Page: 211
[Figure 62]
Page: 213
[Figure 63]
Page: 219
[Figure 64]
Page: 221
[Figure 65]
Page: 224
[Figure 66]
Page: 226
[Figure 67]
Page: 242
[Figure 68]
Page: 242
[Figure 69]
Page: 254
[Figure 70]
Page: 255
[Figure 71]
Page: 260
[Figure 72]
Page: 263
[Figure 73]
Page: 267
[Figure 74]
Page: 268
[Figure 75]
Page: 272
< >
page |< < (10) of 279 > >|
    <echo version="1.0RC">
      <text xml:lang="it" type="free">
        <div xml:id="echoid-div11" type="section" level="1" n="9">
          <pb o="10" file="0022" n="23" rhead="CAPO II."/>
        </div>
        <div xml:id="echoid-div13" type="section" level="1" n="10">
          <head xml:id="echoid-head14" xml:space="preserve">QVESTIONE PRIMA.</head>
          <head xml:id="echoid-head15" xml:space="preserve">Come ſi troua la parte determinata in numeri
            <lb/>
          d’ vna linea data.</head>
          <p>
            <s xml:id="echoid-s187" xml:space="preserve">SIa data la linea MN longhezza della Cortina in vn diſ-
              <lb/>
            ſegno di qualche Fortezza, e volendoſi prendeie la dif-
              <lb/>
            feſa dal quinto della Cortina, ſi cerchi la ſua
              <lb/>
              <figure xlink:label="fig-0022-01" xlink:href="fig-0022-01a" number="7">
                <image file="0022-01" xlink:href="http://echo.mpiwg-berlin.mpg.de/zogilib?fn=/permanent/library/xxxxxxxx/figures/0022-01"/>
              </figure>
            quinta parte. </s>
            <s xml:id="echoid-s188" xml:space="preserve">Allarghiſi lo Stromento in mo-
              <lb/>
            do, che la diſtanza 100. </s>
            <s xml:id="echoid-s189" xml:space="preserve">100. </s>
            <s xml:id="echoid-s190" xml:space="preserve">ſia la MN: </s>
            <s xml:id="echoid-s191" xml:space="preserve">poi
              <lb/>
            eſſendo 20. </s>
            <s xml:id="echoid-s192" xml:space="preserve">la quinta parte di 100. </s>
            <s xml:id="echoid-s193" xml:space="preserve">ſi pigli la
              <lb/>
            diſtanza 20. </s>
            <s xml:id="echoid-s194" xml:space="preserve">20, ritenendo la ſteſſa apertura
              <lb/>
            dello ſtromento, e queſta ſara la MO quinta
              <lb/>
            parte cercata di MN. </s>
            <s xml:id="echoid-s195" xml:space="preserve">Mà ſe la linea foſſe tale,
              <lb/>
            che la parte cercata foſſe molto piccola, ſi
              <lb/>
            prenda l’interuallo del reſto: </s>
            <s xml:id="echoid-s196" xml:space="preserve">come nella figu-
              <lb/>
            ra antecedente; </s>
            <s xml:id="echoid-s197" xml:space="preserve">ſe della linea RS ſi deſidera
              <lb/>
            la parte trenteſima, s’applichi RS all’ interual-
              <lb/>
            lo 30. </s>
            <s xml:id="echoid-s198" xml:space="preserve">30. </s>
            <s xml:id="echoid-s199" xml:space="preserve">& </s>
            <s xml:id="echoid-s200" xml:space="preserve">à quell’a pertura ſi prenda l’inter-
              <lb/>
            uallo 29. </s>
            <s xml:id="echoid-s201" xml:space="preserve">29. </s>
            <s xml:id="echoid-s202" xml:space="preserve">& </s>
            <s xml:id="echoid-s203" xml:space="preserve">il Compaſſo tagliando 29 par-
              <lb/>
            ti della linea RS, laſcierà vna trenteſima. </s>
            <s xml:id="echoid-s204" xml:space="preserve">Preſo
              <lb/>
            dipoi l’interuallo 28 28. </s>
            <s xml:id="echoid-s205" xml:space="preserve">e queſto applicato al-
              <lb/>
            la linea RS, laſcierà due trenteſime, e così di
              <lb/>
            mano in mano. </s>
            <s xml:id="echoid-s206" xml:space="preserve">Se bene fatta la prima ope-
              <lb/>
            ratione, ſe l’interuallo Si è di parti 29, vgua-
              <lb/>
            le à queſto ſia R e, ſimilmente di parti 29: </s>
            <s xml:id="echoid-s207" xml:space="preserve">la
              <lb/>
            diſtanza i e è di particelle 28: </s>
            <s xml:id="echoid-s208" xml:space="preserve">queſta dunque
              <lb/>
            applicata da S, darà S u parti 28: </s>
            <s xml:id="echoid-s209" xml:space="preserve">così u e ſarà
              <lb/>
            parti27.</s>
            <s xml:id="echoid-s210" xml:space="preserve">
              <unsure/>
            e perciò queſta applicata da S, darà S @
              <lb/>
            di parti 27; </s>
            <s xml:id="echoid-s211" xml:space="preserve">e cosi dell’altre.</s>
            <s xml:id="echoid-s212" xml:space="preserve"/>
          </p>
        </div>
      </text>
    </echo>
Impressum