Huygens, Christiaan, Christiani Hugenii opera varia; Bd. 1: Opera mechanica

Table of figures

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[111] Fig. 2.G B R F
[112] Fig. 3.A E C F B
[113] Fig. 4.A C E D F B
[114] Fig. 6.A B C G D L
[115] Fig. 5.H A O M R L N
[116] Pag. 166.TAB.XXV.Fig. 1.A O C G D L N
[117] Fig. 2.A B C G D L N
[118] Fig. 3.O C D A K B N E F C D L M
[119] Fig. 4.O A C D F E K B N C L D M
[120] Fig. 5.E A G F H K B D C
[121] Pag. 170.TAB. XXVI.Fig. 1.Ω O Ω A Z R F R N E N R G S V P Φ Δ V B D K C
[122] Fig. 2.L O A V P Φ Δ V B E C S H D
[123] Fig. 3.F G E G P A P K K L B D B S
[Figure 124]
[Figure 125]
[126] Pag. 188.TAB.XXVII.Fig. 1.O V VA M N D N B O E CE A G B D C F
[127] Fig. 2.S Z G F H Y
[128] Fig. 3.D A D M T C
[129] Fig. 4.A E N D C
[130] Fig. 5.K D B G A F E H
[Figure 131]
[Figure 132]
[Figure 133]
[Figure 134]
[Figure 135]
[Figure 136]
[137] Pag. 248.TAB. XXVIII.Fig. 1.B A E D H F I G
[138] Fig. 2.M B A E D L N H F O I G
[139] Fig. 4.O P M I B G Q N L R H A F D
[140] Fig. 5.B A D L N H I
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11472CHRISTIANI HUGENII
Item rurſus oſtenditur angulus L V C major L C V. Qua-
11De de-
SCENSU
GRAVIUM.
re C V P, qui cum L V C duos rectos æquat, minor erit
quam V C D.
Atqui addendo ad V C D angulum D C N,
fit V C N;
& auferendo ab C V P angulum P V N, fit
C V N.
Ergo angulus V C N omnino major quam C V N.
In triangulo itaque C V N, latus V N majus erit quam
C N.
Eſt autem ipſi V N æqualis C A ſive C M. Ergo &
C M major quam C N, ideoque punctum circumferentiæ
M erit ultra curvam N A B à centro C remotum.
Itaque
conſtat circumferentiam M A F tangere curvam in puncto A.

quod erat demonſtrandum.
Quod ſi punctum curvæ per quod tangens ducenda eſt,
ſit illud ipſum ubi regula curvam ſecat, erit tangens quæſi-
ta ſemper regulæ perpendicularis;
ut facile eſſet oſtendere.
PROPOSITIO XVI.
SI circuli circumferentiam, cujus centrum E, ſe-
22De motu
IN Cy-
CLOIDE.
cent rectæ duæ parallelæ A F, B G, quarum
33TAB. VIII.
Fig. 2.
utraque ad eandem partem centri transeat, vel
altera A F per centrum ipſum:
& à puncto A,
quo centro propior circumferentiam ſecat, ducatur
recta ipſam contingens:
dico partem hujus A B, à
parallela utraque interceptam, minorem eſſe arcu
A C, ab utraque eadem parallela intercepto.
Ducatur enim arcui A C ſubtenſa recta A C. Quia ergo
angulus B A F eſt æqualis ei quem capit portio circuli A H F,
quæ vel major eſt ſemicirculo vel ſemicirculus, erit proinde
angulus B A F, vel minor recto vel rectus;
ideoque angu-
lus A B C vel major recto vel rectus.
Quare in triangulo
A B C latus A C, angulo B ſubtenſum, majus erit latere
A B.
ſed idem latus A C minus eſt arcu A C. Ergo omni-
no &
A B arcu A C minor erit.

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