Barrow, Isaac, Lectiones opticae & geometricae : in quibus phaenomenon opticorum genuinae rationes investigantur, ac exponuntur: et generalia curvarum linearum symptomata declarantur

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28491 R. FZ; erit ſpatium ADLK æquale rectangulo ex R, & DB.
Nam ſit DH = R; & compleatur rectangulum BDHI; tum
aſſumptâ MN indeſinitè parvâ curvæ AB partìculâ ducantur NG ad
BD;
& MEX, NOS ad AD parallelæ. Eſtque NO. MO: :
TF.
FM: : R. FZ. Unde NO x FZ = MO x R; hoc eſt FG
x FZ = ES x EX.
ergò cum omnia rectangula FG x FZ minimè
differant à ſpatio ADLK;
& omnia totidem rectangula ES x EX
componant rectangulum DHIB, ſatìs liquet Propoſitum.
XX. Iiſdem poſitis, ſit curva PYQ talis, ut ſumpta in ſumpta
recta MX ordinata EY (reſpectivæ) ipſi FZ æquetur, erit _ſumma_
_quadr atorum_ ex FZ (ad rectam AD computata) par ei quod fit ex
ipſa R in _ſpatium_ DBQB ducta.
Eſt enim FG. ES: : NO. MO: : R x FZ. FZq: : R x EY.
FZq. adeóque FG x FZq = ES x R x EY.
XXI. Simili ratione _ſumma Cuborum_ ex FZ æquatur ei quod fit ex R
in ſummam quadratorum ex rectis EY ad BD applicatis.
neque non ſi-
mili quoad reliquas poteſtates tenore.
XXII. Sit curva quævis DOK, in qua deſignatum punctum D;
11Fig. 128.& ſubtenſa recta DK; ſit item curva AE talis, ut à D projectâ quâ-
vis rectâ DMF (quæ curvas ſecet punctis M, F) ductíſque DS ad
DM normali, &
MS curvam DOK tangente (concurrentibus utiq;
puncto S) datâque quâdam R, ſit DS. 2 R: : DMq. DFq; erit
ſpatium ADE æquale ex R, DK.
Nam ſubtenſa DK indefinitè ſecta concipiatur punctis PQ, & c.
per quæ centro C deſcripti tranſeant arcus PM, QRN; curvam
DOK ſecantes punctis M, N;
per quæ ducantur rectæ DMF,
DNG;
ſint verò DT ad DK; & DS ad DM perpendiculares;
quibus occurrant tangentes KT, MS.
demùm centro D per E duca-
tur arcus EX;
& per F arcus FY. Jam, ob ſectionem indefinitam,
eſt triangulum KPM triangulo KDT ſimile.
ac ideò MP. PK: :
TD.
DK. item eſt DP. PM: : DE. EX. ſeu, propter aſſigna-
tam cauſam, DK.
MP: : DE. EX. Eſt itaque MP x DK. PK x
MP:
: TD x DE. DK x EX. hoc eſt DK. PK: : TD x DEq.
DK x EX x DE.
ac inde DKq x EX x DE = PK x TD x
DEq.
(_a_) Eſt autem DT. 2 R: : DKq. DEq; ſeu DT x DEq
22(_a_) _Hyp._ = 2 R x DKq.
ergò eſt DKq x EX x DE = PK x 2 R x DKq.
quare EX x DE = 2 R x PK; hoc eſt, 2 ſector DEX = 2 R x PK.
unde ſector DEX = R x PK.
Simili planè diſcurſu ſector

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