SInt duo polygona complicata
11
A B # A
C D # C
E F # G
K L # H
Z # X
A, B, nempe A intra circuli
vel ellipſeos ſectorem, B extra.
continuetur ſeries convergens ho-
rum polygonorum complicato-
rum ſecundum methodum no-
ſtram ſubduplam deſcriptorum;
ita ut polygona intra circulum ſint A, C, E, K, & c, & ex-
tra circulum B, D, F, L, & c; ſitque ſeriei convergentis ter-
minatio ſeu circuli vel ellipſeos ſector Z. dico Z majorem
eſſe quam C una cum triente exceſſus C ſupra A. ſit exceſſus
G ſupra C quarta pars exceſſus C ſupra A, & exceſſus H
ſupra G quarta pars exceſſus G ſupra C; continueturque
hæc ſeries in infinitum, ut ejus terminatio ſit X. Exceſſus
C ſupra A minor eſt quadruplo exceſſus E ſupra C; & ideo
exceſſus E ſupra C major eſt exceſſu G ſupra C, eſt ergo
E major quam G. deinde exceſſus E ſupra C minor eſt qua-
druplo exceſſus K ſupra E, & ideo exceſſus G ſupra C mul-
to minor eſt quadruplo exceſſus K ſupra E, eſt igitur
11
A B # A
C D # C
E F # G
K L # H
Z # X
A, B, nempe A intra circuli
vel ellipſeos ſectorem, B extra.
continuetur ſeries convergens ho-
rum polygonorum complicato-
rum ſecundum methodum no-
ſtram ſubduplam deſcriptorum;
ita ut polygona intra circulum ſint A, C, E, K, & c, & ex-
tra circulum B, D, F, L, & c; ſitque ſeriei convergentis ter-
minatio ſeu circuli vel ellipſeos ſector Z. dico Z majorem
eſſe quam C una cum triente exceſſus C ſupra A. ſit exceſſus
G ſupra C quarta pars exceſſus C ſupra A, & exceſſus H
ſupra G quarta pars exceſſus G ſupra C; continueturque
hæc ſeries in infinitum, ut ejus terminatio ſit X. Exceſſus
C ſupra A minor eſt quadruplo exceſſus E ſupra C; & ideo
exceſſus E ſupra C major eſt exceſſu G ſupra C, eſt ergo
E major quam G. deinde exceſſus E ſupra C minor eſt qua-
druplo exceſſus K ſupra E, & ideo exceſſus G ſupra C mul-
to minor eſt quadruplo exceſſus K ſupra E, eſt igitur