Clavius, Christoph
,
Geometria practica
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358
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GEOMETR. PRACT.
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<
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quoque ſine vllo labore dato cuicunq; </
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<
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xml:space
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">circulo quadratum æquale ex-
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hibeamus, vtendum erit hoc artificio. </
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<
s
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xml:space
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">Inuento ſemellatere quadrati alicui cir-
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xlink:label
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note-358-01
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xml:space
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">Facilis inuen-
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tio quadrati
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circulo æqua-
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lis.</
note
>
culo æqualis, vt paulò ante docuimus, conſtruemus figuram ad quadrandos
<
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alios circulos quo ſcunque accommodatiſsimam, hoc modo. </
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<
s
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xml:space
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">Detur circulus
<
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A B C, diametri A C, ſitque A B, media proportionalis inter ſemidiametrum,
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& </
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<
s
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xml:space
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">rectam ſemicircumferentiæ æqualem inuentam ex præcedenti figura, ita vt
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quadratum rectæ AB, circulo diametri A C, ſit æquale: </
s
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<
s
xml:id
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xml:space
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"> accommodetur AB,
<
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xml:space
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">1. quinti.</
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circulo, quæ certius applicabitur, ſi fortè circinus ex A, ad interuallũ datæ AB,
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deſcriptus nimis oblique peripheriam A B C, ſecet in B, hoc modo. </
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<
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">Duabus
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rectis, nimirum diametro AC, & </
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>
<
s
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xml:space
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">lateri AB, quadrati inuento reperiatur tertia ꝓ-
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portionalis AD. </
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<
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xml:space
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">Perpendicularis namque DB, cadet in punctum B, in quod la-
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xml:space
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">coroll. 8.
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ſexti.</
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tus inuentum duci debet: </
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<
s
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xml:space
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"> propterea quod tres rectæ AC, AB, AD, ſunt conti- nuè proportionales, quemadmodum recta A C, latus quadrati inuentum, & </
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AD, continuam ſeruant proportionem, ex conſtructione. </
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>
<
s
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xml:space
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">Liquet autem inter
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AC, AD, vnam tantum poſſe eſſe mediam proportionalem. </
s
>
<
s
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xml:space
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">Hac figura extru-
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cta, dicto citius quemcunque circulum quadrabimus. </
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<
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xml:space
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">Sinamque diametro da-
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ti circulirectam æqualem abſcindemus A F, circa quam ſemicirculus deſcriba-
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tur, reſecabit is ex recta AB, latus AE, cuius quadratum circulo dato eſt æqua-
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http://echo.mpiwg-berlin.mpg.de/zogilib?fn=/permanent/library/xxxxxxxx/figures/358-01
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le. </
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<
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">Quia enim angulus externus AEF, inter-
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no ABC, æqualis eſt: </
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<
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xml:space
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"> quod vterque in
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xml:space
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">31. tertii.</
note
>
circulo rectus ſit; </
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<
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"> erunt E F, B C, parallelæ;</
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<
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<
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symbol
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position
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xlink:label
="
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xml:space
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">28. primi.</
note
>
ideoque triangula AEF, ABC, æquiangula. </
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<
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<
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e
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position
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xlink:label
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xml:space
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">4. ſexti.</
note
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Igitur erit CA, ad AB, vt FA, ad AE; </
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<
s
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xml:space
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">Et permu-
<
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tando CA, ad FA, vt AB, ad AE. </
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>
<
s
xml:id
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xml:space
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"> Ideoque
<
note
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f
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xml:space
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">22. ſexti.</
note
>
rit quoque quadratum ex AC, ad quadratum
<
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ex A F: </
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<
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xml:space
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"> hoc eſt, vt circulus diametri A C,
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xml:space
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">2. duodec.</
note
>
circulum diametri A F, vt quadratum ex A B,
<
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ad quadratum ex AE. </
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<
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xml:space
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">Eſt autem circulus dia-
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metri A C, quadrato ex A B, per conſtru ctio-
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nem, ęquale. </
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>
<
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xml:space
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"> Igitur & </
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>
<
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">circulus diametri
<
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xlink:label
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note-358-09
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xml:space
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">14. quinti.</
note
>
quadrato ex AE, æquale erit. </
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<
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xml:space
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">Ita quo que qua-
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dratum rectæ A G, circulo diametri A H, erit
<
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ęquale. </
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>
<
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xml:space
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">Et ſic de cęteris.</
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>
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</
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<
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<
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verò quoniam lib. </
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<
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">4. </
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<
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<
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</
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<
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xlink:label
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xlink:href
="
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xml:space
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">Facilis inuen-
<
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tio quadrati-
<
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circulo æqua-
<
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lis ex Archi-
<
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mede.</
note
>
3. </
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<
s
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xml:space
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">ex Archimede demonſtrauimus, quadratũ
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diametri ad circulum habere ferme propor-
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tionem, quam 14. </
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<
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">ad 11. </
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<
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">ſi quis volet ſecundũ
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hanc proportionem reperire quadratum cir-
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culo æquale; </
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<
s
xml:id
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xml:space
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">diuidenda erit recta A C, in 14.
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</
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<
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">partes æquales, & </
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<
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xml:space
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">ex vndecima parte D, (ita vt AD, contineat partes 11. </
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<
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">& </
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<
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3.) </
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<
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xml:space
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">ex citanda perpendicularis DB, vſque ad circumferentiam circa A C, deſcri-
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ptam. </
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<
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xml:space
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">Recta enim enim ducta A B, latus erit quadrati circulo diametri A C, æ-
<
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<
note
symbol
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i
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xlink:label
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xlink:href
="
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xml:space
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">coroll. 2.
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ſexti.</
note
>
qualis. </
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<
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"> Cum enim tres rectæ AC, AB, AD, ſint continue proportionales; </
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>
<
s
xml:id
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xml:space
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"> erit quadratum ex A C, ad quadratum ex A B, vt A C, ad A D, videlicet vt 14. </
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>
<
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">ad 11.
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</
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<
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<
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k
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position
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xlink:label
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xlink:href
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xml:space
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">coroll. 20.
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ſexti.</
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>
Cum ergo etiam ſit, vt diximus, quadratum diametriad circulum, vt 14. </
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<
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">ad 11.
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</
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<
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">ferme: </
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>
<
s
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xml:space
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"> erit quadratum ex AC, ad quadratum ex AB, vt ad circulum
<
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l
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xlink:label
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xml:space
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">11. quinti.</
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>
AC. </
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<
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"> Igitur quadratum ex AB, circulo diametri A C, æquale erit. </
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<
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">Quod ſi
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